Question

Aniline, a starting material for urethane plastic foams, consists of C, H, and N. Combustion of such
compounds yields CO 2 , H 2 O, and N 2 as products. If the combustion of 9.71 g of aniline yields 6.63 g
H 2 O and 1.46 g N 2 , what is its empirical formula?

Answer 1

Answer:

Yes, or more accurately

4C6H7N + 31O2 ==> 24CO2 + 14H2O + 2N2

BUT you don't need the equation.

Convert 6.63 mg H2O to mg H.

You have 1.46 mg nitrogen ATOMS.

Calculate mg C from 9.71-mg N - mg H.

Convert mg C to moles.

Convert mg H to moles.

Convert mg N to moles.

Now you want to determine the ratio of these elements to each other in small whole numbers. The easiest way to do that is to divide the smallest number by itself. Then divide the other numbers by the same small number. Round to whole numbers. That should give you the empirical formula.

Is the molar mass of 372.504 part of the same problem