Question

Aniline was diazotized and was subsequetly reduced with tin (11)chloride and Hcl.the product formed is

Answer 1

the product will be phenylhydrazine

Answer 2

When aniline was diazotized and reduced with tin(II) chloride and HCl, the product formed is Phenylhydrazine.

• Aniline on diazotization i.e when aniline reacts with Sodium nitrate and hydrogen chloride at 0-5°C it forms a diazonium salt called benzene diazonium chloride.
• The diazonium salt when reduced with tin(II) chloride and HCl forms a product called Phenylhydrazine.

Aniline on diazotization:

$C_{6} H_{5} NH_{2} + NaNO_{2}$ → $C_{6} H_{5} N_{2} ^{+} Cl^{-}$

Reduction with Tin(II) chloride and HCl

$C_{6} H_{5} N_{2} ^{+} Cl^{-} + SnCl_{2} + HCl$ → $C_{6} H_{5}NHNH_{2}$

Hence, when aniline was diazotized and reduced with tin(II) chloride and HCl, the product formed is Phenylhydrazine.