Question

Anita borrowed rupees 50000 for 1 year 5 months at 12% per annum compounded annually how much money will she have to pay back to settle the account

Answer 1

50000÷25=2000===2000×28=400000

Answer 2

$priciple \: {p} = 50000 \\ rate = 12\% \\ time = 1 \\ amount= p(1 + \frac{r}{100} ) \sqrt{n } \\ amount = 50000(1 + \frac{12}{100} ) \sqrt{1} \\ amount= 50000(100 + 12) \div 100 \\ amount= 50000 \times \frac{112}{100} \\ amou \: t= 500 \times 112 \\ amount \: = 5600 \\ therefore \: interest \: for \: 1 \: year \: is \: amount - principal \\ 56000 - 50000 \\ 6000 \\ p = 56000 \\ r = 12\% per \: yearly \\ per \: half \: year \: \frac{12\%}{2} = 6\% \\ \: time = 1 \times 2 \: half \: yearly =2 \: half \: yearly \\ si = p \times r \times t \div 100 \\ si = 56000 \times 6 \times 2 \div 100 \\ si = 560 \times 12 \\ si = 6720 \\ she \: have \: to \: pay \: 56000 + 6720 = 62720$