Anita got married 9 years ago. today her age 4/3 times her age at the time of marriage.at present ,her daughter's age is one-sixth of her age.what was her daughters age two years ago
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anita's age during marraige= x
anita's present age= x+9=4x/3
3(x+9)=4x
3x+27=4x
27=4x-3x
x=27
therefore her present age=x+9=27+9=36
her daughters age is 1/6 th her age=36/6=6 years
her daughters age two years ago=6-2=4
hope it helped!!!
and dont forget to mark as brainliest
anita's age during marraige= x
anita's present age= x+9=4x/3
3(x+9)=4x
3x+27=4x
27=4x-3x
x=27
therefore her present age=x+9=27+9=36
her daughters age is 1/6 th her age=36/6=6 years
her daughters age two years ago=6-2=4
hope it helped!!!
and dont forget to mark as brainliest
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