Question

Anita is twice as old as her brother. In 6 years from now the sum of their ages will be 39.How old are they now.? ​

Answer 1

Step-by-step explanation:

Let us assume Anita's brother's age as X. As Anita is twice as old as her brother her age would be 2X.

In 6 years from now there ages would be

Anita's age = 2X + 6, Anita's brother's age =X +6

So, according to the question, the sum of there ages after 6 years is 39.

Now the equation would be (2X+6) + (X+6) = 39

After solving the above equation we get, X=9

Now 2X=18 and X=9

So, Now the age of Anita is 18 .i.e. 2X and her brother's age is 9 .i.e. X.

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Thank you, NS.

Answer 2

Answer:

Let Anita's Brother age =x

∴ Anita Age ⇒2x

Six year after

Anita age ⇒2x+6

Brother Age =x+6

Ace to Ques.

(2x+6)+(x+6)=39

3x+12=39

3x=27,=9

∴ Anita Brother Age ⇒9 years (x)

Anita Age ⇒18 years (2x)

Step-by-step explanation: