Math, asked by singhsandeep79045, 8 months ago

Anita is twice as old as her brother. In 6 years from now the sum of ages will be 39.How old are they now.?​

Answers

Answered by harmandeepsinghtoki
0

Answer:

Let Anita's Brother age =x

∴ Anita Age ⇒2x

Six year after

Anita age ⇒2x+6

Brother Age =x+6

Ace to Ques.

(2x+6)+(x+6)=39

3x+12=39

3x=27,=9

∴ Anita Brother Age ⇒9 years (x)

Anita Age ⇒18 years (2x)

Answered by LEGEND778
0

Answer:

Anita's brothers age is 9 years and her age is 18 years as of now.

Step-by-step explanation:

Let us assume Anita's brothers age as x.

As we assume her brothers age as x her age will be 2x according to question.

Anita's age after 6 years = 2x + 6

Anita's brothers age after 6 years = x + 6

In the question the sum of their ages is given as 39.

So the equation would be:

2x + 6 + x + 6 = 39

Now solving this equation:

2x + 6 + x + 6 = 39

3x + 12 =39

3x = 39 - 12 = 27

3x = 27

x = 27/3

∴ x = 9

Therefore Anita's brothers age is 9 years and her age is 2x which is 9 * 2 = 18 years as of now.

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