Anita is twice as old as Mahesh.Ten years ago, Anita was seven times as old as Mahesh.Find their present ages
Answers
Answered by
3
Let at present
mahesh age x years
anita age =2x years
10 years ago
mahesh age=(x-10) years
anitha age=(2x-10) years
given
anita age =7×mahesh age
2x-10=7(2x-10)
2x-10=14 x-70
70-10=14x-2x
60=12x
60/12=x
x=5
therefore
at present
mahesh age=x=5 years
anita age=2x=2×5=10 years
mahesh age x years
anita age =2x years
10 years ago
mahesh age=(x-10) years
anitha age=(2x-10) years
given
anita age =7×mahesh age
2x-10=7(2x-10)
2x-10=14 x-70
70-10=14x-2x
60=12x
60/12=x
x=5
therefore
at present
mahesh age=x=5 years
anita age=2x=2×5=10 years
Similar questions