Anita is twice as old as mahesh . Ten years ago , anita was seven times as old as mahesh . find thier present ages
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Let the present age of Mahesh be x
Anita is twice as old as Mahesh
so present age of Anita is 2x
before ten years
Anita age = 2x - 10 years
Mahesh's age = x - 10 years
by the condition given in your question we get equation
( 2x - 10 ) = ( X - 10 ) 7
2x - 10 = 7x - 70
70 - 10 = 7x - 2x
5x = 60
x = 12 years
so the age of Mahesh is 12 years and the age of Anita is 24 years
Anita is twice as old as Mahesh
so present age of Anita is 2x
before ten years
Anita age = 2x - 10 years
Mahesh's age = x - 10 years
by the condition given in your question we get equation
( 2x - 10 ) = ( X - 10 ) 7
2x - 10 = 7x - 70
70 - 10 = 7x - 2x
5x = 60
x = 12 years
so the age of Mahesh is 12 years and the age of Anita is 24 years
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