Question

Anita is twice as old as Mahesh. Ten years ago, Anita was seven times as old as Mahesh find their present age

Answer 1

let Mahesh age =x

anita =2x

10 years ago

anita=2x-10

mohan=x-10

(2x-10)=7(X-10)

2x-10=7x-70

5x=60

x=12 i.e. mohan age is 12

and anita is twice as old as mahesh so 24

Answer 2

Let Mahesh be x years old.

.

Now:

Mahesh = x

Anita = 2x

.

10 years ago:

Mahesh = x - 10

Anita = 2x - 10

.

10 years ago, Anita was 7 times as old as Mahesh:

2x - 10 = 7(x - 10)

.

Solve x:

2x - 10 = 7(x - 10)

2x - 10 =7x - 70

7x - 2x = 70 - 10

5x = 60

x = 12

.

Find their present age:

Mahesh = x = 12

Anita = 2x = 2(12) = 24

.

Answer: Mahesh is 12 years old and Anita is 24 years old.