Question

Anita travels at 90 m every 12 seconds while Sanhita travels at 960 m every 2 minute 30 seconds.

Travelling from the same point at the same time they head in opposite directions. What will be the

distance between them after 1 hour from the start?​

Answer 1

Answer:

Two buses starting from two different places A and B simultaneously, travel towards each other and meet after a specified time. If the bus starting from A is delayed by 20 minutes, they meet 12 minutes later than the usual time. If the speed of the bus starting from A is 60km/hr, what is the speed of the second bus?

My attempt:

Let t be the usual time of meeting and s(A) and s(B) be the speeds of Bus A and Bus B respectively, then

Applying relative velocity concept (stopping bus B i.e. taking it's speed =0 and adding it to speed of A), i got:

s(A)= 60 (given)

(60 + s(B))t = d (distance between the buses)

Now if bus A is delayed by 20 mins, then B's travelling time is 20 mins more than A's to cover the same distance.

t(B) = t(A) + 20/60

hence, t(B)= t(A) + 1/5

distance covered by A = t(A) * 60

distance covered by B = t(B) * s(B) = (t(A) +1/5)*s(B)

Step-by-step explanation:

Hope this answer will help you.