Question

Anita was selling meal tickets for a social cause at her school. The cost of dinner is $10, and if anyone
wanted dessert it is an additional $12. she lost track of how many of each ticket she sold. However
she remembers that she was given 100 tickets and she collected $1120. How many meals with
desserts did she sell?​

Answer 1

Answer:

10 meals and 12 desserts

Answer 2

Step-by-step explanation:

Let the number of meals be x and the number of desserts be y.

By the given conditions,

• x + y = 100 ... (1)
• 10x + 12y = 1120 ... (2)

From (1), we get y = 100 - x, and substitute this value in (2). We get

• 10x + 12 (100 - x) = 1120
• or, 10x + 1200 - 12x = 1120
• or, 2x = 80
• or, x = 40

Putting x = 40 in (1), we get

• 40 + y = 100
• or, y = 60

Here x ≠ y, but if we take x = 40 = y, we see that (60 - 40) = 20 desserts were sold single.

Answer: She sold 40 meals with desserts.