Anitha collected a sum of rs 150 in a bank.she had put into it only rs 2 rs 5 and rs 10 .if rs 10 and rs 5 coins are in the ratio 3:7 and there are 30 coins.find the number of coins in each type I need full steps
Answers
number of Rs 10 coins = 3x
number of Rs. 5 coins = 7x
number of Rs 2 coins = 30 - 3x +7x = 30 - 10x
total rs = 150
(3x X 10) + (7x X 5) + 2(30 - 10x) = 150
30x + 35x + 60 - 20x = 150
45x = 150 - 60
x = 90/45 = 2
Number of 10 rupee note = 3x= 6
Number of 5 rupee note = 7x = 14
Number of 2 rupee note = 30 - 10x = 30 - 20 = 10
Ratio of Rs10 : Rs5 = 3 : 7 (Given))
Define x:
Let x the constant ratio:
Ratio of Rs 10 : Rs 5 = 3x : 7x
Find the number of Rs 2 coins expressed in x:
number of Rs 2 coins = 30 - 3x - 7x = 30 - 10x
Solve x:
Given that the total sum is Rs 150
10(3x) + 5(7x) + 2(30 - 10x) = 150
30x + 35x + 60 - 20x = 150
45x = 90
x = 2
Find the number of coins each:
Rs 10 = 3x = 3(2) = 6
Rs 5 = 7x = 7(2) = 14
Rs 2 = 30 - 7x = 30 - 10(2) = 10
Answer: There are 10 Rs 2, 14 Rs 5 and 6 Rs 10