Question

Anitially
at
the
A Force acts for 10 s
body of
10-2
rest. after
kg
after which
ecoses (come
an end)
act. The
travels 05m
the
next
55. Find the
itude
the
fore.
tone
to en
The body
ta
magnitude
of
(
A
B
10-IN
10-4N
10-t N
10-9
10-1.N​

Answer 1

Answer:

The magnitude of force = 10⁻⁴ N

Explanation:

Correct Question : A force acts for 10 s on a body of mass 10⁻² kg initially at rest after which the force ceases come to an end to act. The body travels 0.5 m in the next 5 s. Find the magnitude of the force.

Let the body starts from rest.

∴ u = 0

Final velocity = distance / time

⇒ Final velocity = 0.5/5 = 0.1 m/s

⇒ Final Velocity = = 0.1 m/s

v = u + at

⇒ a = (v-u)/t

Here,

• v = 0.1 m/s
• u = 0 m/s
• t = 10 s

∴ a = (0.1 - 0)/10

⇒ a = 0.1/10

⇒ a = 0.01 m/s²

Force(F) = Mass(m) × Acceleration(a)

Here,

• Mass = 10⁻² kg = 1/100 kg = 0.01 kg
• Acceleration = 0.01 m/s²

∴ F = 0.01 × 0.01

⇒ F = 0.0001 N

⇒ F = 10⁻⁴ N

Answer 2

ANSWER

initial velocity is 0

then, v=u+at

v=0+a10

v=10a

After 10s body starts moving and covers 50m in 5s

S=vt

50=(10a)5

a=1m/s

2

using the value of a in F=ma

F=10×1=10N