Anjali saves Rs 32 during the first month and rupees 36 in second month and rupees 40 in 3rd month she continues to save in this manner in how many month will she save 2000 rupees
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Hey mate,
It is an AP 32,36,40.......n
We have,
Sn=2000
a=32, d=4
Sn=n/2 [2a+(n-1)d]
2000=n/2[64+4n-4]
4000=4n2+60n
4n2+60n-4000=0
n2+15n-1000=0
n2+40n-25n-1000=0
by solving we get n = 25 and -40.
As months cant be negative we take positive value.
Therefore She will save Rs 2000 in 25 months.
hope this helps you out!
It is an AP 32,36,40.......n
We have,
Sn=2000
a=32, d=4
Sn=n/2 [2a+(n-1)d]
2000=n/2[64+4n-4]
4000=4n2+60n
4n2+60n-4000=0
n2+15n-1000=0
n2+40n-25n-1000=0
by solving we get n = 25 and -40.
As months cant be negative we take positive value.
Therefore She will save Rs 2000 in 25 months.
hope this helps you out!
noorainnaaz24680:
Thank uh❤
your most welcome ❤
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