Anjali wants to renovate her hall room which is rectangular in shape with dimensions 6m x 5m. She decided to make the following changes.
Q1. The ceiling (6m x 5m) of the room is to be painted white in colour. The paint covers 10 sq.m per litre and can be purchased in 2 litre tins at Dhs 43.50 per litre.If two coats of paint are required , Find the cost of the paint needed?
Answers
Answer:
Given : hall room rectangular in shape with dimensions 6m x 5m.
base and height of each tile is 60cm and 50 cm respectively.
2m diameter carpet is placed at the center of the hall,
To Find : number of triangular tiles required for the entire room
how much area is left uncarpeted
ratio of area of a triangular tile to area of the carpet placed at the center of the hall.
Solution:
Triangular tiles are congruent using SSS congruence
base and height of each tile is 60cm and 50 cm respectively.
=> area of one tile = (1/2) * 60 * 50 = 1500 cm²
hall room rectangular in shape with dimensions 6m x 5m.
1 m = 100 cm
6 m = 600 cm
5 m = 500 cm
Hall Area = 600 x 500 = 300000 cm²
Number of tiles required = 300000 / 1500 = 200
2m diameter carpet is placed at the center of the hall,
Radius = 1 m = 100 cm
Area of circle = πr²
Area of carpet = 3.14 * 100² = 31400 cm²
= 3.14 m²
area is left uncarpeted = 300000 - 31400
= 2,68,600 cm²
= 26.68 m²
ratio of area of a triangular tile to area of the carpet placed at the center of the hall.
= 30 : 3.14
= 3000 : 314
= 1500 : 157
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