Question

Anjana ran thrice around a rectangular Park of length 275 and breadth 180 metres sonam Run around a square Park of side 95 m five times what distance was covered by both of them who covered more distance and by how much​

Answer 1

Answer:

Perimeter of rectangular park=2(l+b)

=2(275+180)

=2(455)

=910m

Distance covered in 1 round=910m

Distance covered in 3 round=910*3

=2730m

Perimeter of squared park=4*side

=4*95

=380m

Distance covered in 1 round=380m

Distance covered in 5 round=5*380

=1900m

Anjana covers more distance by(2730-1900)830m

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Answer 2

The distance cover by Anjana is 2730 m².

The distance cover by Sonam  is 1900 m².

Anajan covers 830 m² more distance.

Step-by-step explanation:

Consider the provided information.

The perimeter of rectangle is: $P=2(l+b)$

Where l is the length and b is breadth.

The perimeter of square is: $P=4a$

Where a is the side of the square.

Anjana ran thrice around a rectangular Park of length 275 and breadth 180 metres.

First find the perimeter of rectangle.

$P=2(275+180)$

$P=910$

Anjana ran thrice around the rectangular park.

910×3=2730 m²

The distance cover by Anjana is 2730 m².

Sonam Run around a square Park of side 95 m five times

$P=4(95)$

$P=380$

Sonam ran five times around the square park.

380×5=1900 m²

The distance cover by Sonam  is 1900 m².

Hence, Anjana covers more distance as compare to Sonam.

2730-1900=830 m²

Anajan covers 830 m² more distance.

#Learn more

The sides of the rectangle are in the ratio 2:three and perimeter is 20cm draw the rectangle

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