anju invested Rs 12000 at 5 percent per annum compound interest . after how many years will her investment amount to Rs 13230 .
Answers
Answered by
10
Principal = 12000 Rs
After 1 year he paid back Rs 4000
Let the rate of interest be x
Hence the principle after 1 year 12000
(1+x/100)-4000
= {12000(1+x/100)-4000 +920}
=> (1+x / 100)= {12000(1+x / 100)-4000 +920}
/{12000(1+x / 100)-4000}
=> (1+x/100)= {8920+120x } /{8000+120x}
=> x/100= {8920+120x}/{8000+120x} - 1
=> x/100 = 920/8000+120x
=> 120x2+8000r-92000 = 0
=> 3x2+200x-2300=0
=> 3x2 -30x+230x - 2300=0
=> 3x(x-10)230(x-10)=0
=> (3x + 230)(x -10)=0
.......
rate of interest =10%
*******************************************
initial principle = 12000
C.I for 1st year = 12000(1+10/100)-12000
=13200-12000=1200
-----------
C.I. for 2nd year =920
⚪ sum of principle and interest of both years
=. 12000+1200+920=14120
-------. paid back 4000
⚪⚪⚪ Hence amount of debt at the end of 2nd year = 14120-4000= 10120 Rs.
After 1 year he paid back Rs 4000
Let the rate of interest be x
Hence the principle after 1 year 12000
(1+x/100)-4000
= {12000(1+x/100)-4000 +920}
=> (1+x / 100)= {12000(1+x / 100)-4000 +920}
/{12000(1+x / 100)-4000}
=> (1+x/100)= {8920+120x } /{8000+120x}
=> x/100= {8920+120x}/{8000+120x} - 1
=> x/100 = 920/8000+120x
=> 120x2+8000r-92000 = 0
=> 3x2+200x-2300=0
=> 3x2 -30x+230x - 2300=0
=> 3x(x-10)230(x-10)=0
=> (3x + 230)(x -10)=0
.......
rate of interest =10%
*******************************************
initial principle = 12000
C.I for 1st year = 12000(1+10/100)-12000
=13200-12000=1200
-----------
C.I. for 2nd year =920
⚪ sum of principle and interest of both years
=. 12000+1200+920=14120
-------. paid back 4000
⚪⚪⚪ Hence amount of debt at the end of 2nd year = 14120-4000= 10120 Rs.
Similar questions