Math, asked by sukhmandhugga491, 16 days ago

Ankit and Bhanu can complete the math summer project in 10 days and 15 days, respectively. They decided to work together during the vacation, but Bhanu left for a trip after some days. Then Ankit finished the remaining work in 5 days. Find the number of days they worked together.

Solve in step by step please give me ans corre​

Answers

Answered by onlythebrave28
2

Ankit= A, Bhanu= B

(A + B)'s 1 day's work = 1/15+ 1/10= 1/6

Work done by A and B in 2 days = 1/6*2 = 1/3

Remaining work = 1 - 1/3= 2/3

Now,

1/15

work is done by B in 1 day.

So,

2/3 work will be done by B in 15 × 2/3

                                             = 10 days

Hence, the total time taken = 10 + 2 = 12 days.

Answered by naveenkarthickr1
0

Answer:

The correct option is A

12 days

(A + B)'s 1 day's work =

1/15+1/10

= 1/6

Work done by A and B in 2 days =

1/6 × 2 = 1/3

Remaining work = 1

1/3=2/3

Now,

1/15

work is done by A in 1 day.

So,

2/3

work will be done by A in 15 ×

2/3

= 10 days

Hence, the total time taken = 10 + 2 = 12 days.

Similar questions