Question

Ankit bought 2 packs of red pens,1 pack of blue pens, and 3 packs of black pens.The red pen packs have 4 pens each.The blue pen packs and the black pen packs have 3 pens each.He places all his pens in a pen holder.Whay is Ankit's probability of picking a red pen from the pen holder?​

Answer 1

p(red)=8

p(blue)=3

p(black)=9

The probability of red pens=8/20

=4/10

=2/5

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Answer 2

The required probability is $\dfrac{2}{5}$.

Step-by-step explanation:

Consider the provided information.

Ankit bought 2 packs of red pens, and each packs have 4 pens.

Total number of red pens = 8

He bought 1 pack of blue pens, and each pack have 3 pens.

Total number of blue pens = 3

He bought 3 packs of black pens, and each pack have 3 pens.

Total number of black pens = 9

The total number of pens are: 8+3+9=20

$Probability = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$

$Probability = \dfrac{8}{20}$

$Probability = \dfrac{2}{5}$

Hence, the required probability is $\dfrac{2}{5}$.

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