Math, asked by ranjeetschn, 1 year ago

ankit is now 9 years older than bobby in 10 years ankit will be twice as old as bobby was 10 years ago find the present age

Answers

Answered by Panzer786
102
Hiii friend,

Let the present age of bobby be X years.

Age of Ankit = (X+9) years.

Before 10 years age of bobby = (X-10) years.

After 10 years age of Ankit = (X+9+10) = (X+19) years.

According to question,

(X+19) = 2(X-10)

X + 19 = 2X- 20

2X - X = 19 +20

X = 39 years.

Age of bobby = X = 39 years.

And,

Age of Ankit = X +9 = 39 +9 = 48 years.

HOPE IT WILL HELP YOU...... :-)

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Answered by abhi569
38
Let,
Present age of

• bobby = x years
• ankit = (x +9) years

. =============

Age of bobby before 10 years = (x-10) years

After 10 years, according to question,

Ankit's age = 2(Bobby's age before 10 years)

x + 9 + 10 = 2(x - 10)

x + 19 = 2x - 20

19 + 20 = 2x-x

39 = x

Present age of bobby =39
Present age of ankit = (39+9)=48 years

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