Math, asked by jaindarshan296, 1 month ago

ankit's house is at a distance of 6/15 km from the school and iswhar's house is at a distance of 7/9 km from the school. who lives nearer to the school and by how much

please send me the answer of this question because it is very urgent ​​​

Attachments:

Answers

Answered by saludhakne19
0

Answer:

Distance between school and house=1 km 875 m

Now, 1 km =1000m

Distance covered each day =1875×2=3750m

Distance covered in 6 days =3750×6

3750

×6

___________

22500

___________

Therefore, distance covered in 6 days=22,500 m =22.5 or 22 km 500 m.

Answered by mishrarishiraj219
4

Step-by-step explanation:

Distance of Ankit's house = 6/15 km,

Distance of iswhar's house house = x km,

the distance of school = 7/9km.

Now, 1 km =1000m

\frac{6}{15}  + x = \frac{7}{9}

x =  \frac{7}{9}  -  \frac{6}{15}

 \frac{35 - 18}{45}  = \frac{17}{45}

hence, the distance of iswhar's house = 17 / 45.

now comparing.

 \frac{6}{15}  =  \frac{17}{45}

 \frac{18 > 17}{45}

therefore, iswhar's house is near to the school.

Similar questions