Question

Ankit sold two jeans for 990 each on one he gains 10% and on the other he lost 10% find his gain or loss percent in Google translation​

Answer 1

Answer:

hy

your answer is here !

Step-by-step explanation:

Total Pairs of Jeans Ankit had = 2

Cost of each pair = Rs. 990

Now, let's calculate the amount for the first pair.

C.P = Rs.990

Profit = 10% 

Hence profit = Rs.99 

So, the final price will be Rs.990 + 99 = 1089

Now, calculation for the 2nd pair of jeans

C.P = Rs.990

Loss = 10%

Hence, loss = Rs.99

So, the final price will be Rs.990 - 99 = 891

Now, verify profit or loss

Price of 1st pair + Price of 2nd pair = 1089 + 891 = 1,980 

Original price of 1st pair + Original price of 2nd pair = 990 + 990 = 1,980

S.P = C.P, 

Hence , no profit no loss

Hope this answer helps you

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Answer 2

Solution :

$\bf{\red{\underline{\bf{Given\::}}}}$

Ankit sold two jeans for Rs.990 each on one of he gains 10% and on the other he lost 10%.

$\bf{\red{\underline{\bf{To\:find\::}}}}$

The gain or loss percent in whole transaction.

$\bf{\red{\underline{\bf{Explanation\::}}}}$

Let the cost price of 1st jeans be Rs.r

Let the cost price of 2nd jeans be Rs.m

We know that formula of the gain % :

$\boxed{\bf{Gain\:(\%)=\frac{SP-CP}{CP} \times 100}}}}$

$\underbrace{\bf{1_{st}\:Case\::}}}}}$

$\bf{We\:have}\begin{cases}\sf{Selling\:price\:(S.P.)_{1}=Rs.990}\\ \sf{Cost\:price\:(C.P.)_{1}=Rs.r}\\ \sf{Gain\:(\%)=10\%}\end{cases}}$

A/q

$\longrightarrow\tt{Gain\:(\%)=\bigg[\dfrac{(S.P.)_{1}-(C.P.)_{1}}{(C.P.)_{1}} \times 100\bigg]}\\\\\\\longrightarrow\tt{\cancel{10}\%=\bigg[\dfrac{990-r}{r} \times 10\cancel{0}\bigg]}\\\\\\\longrightarrow\tt{\%=\dfrac{9900-10r}{r} }\\\\\\\longrightarrow\tt{r=9900-10r}\\\\\\\longrightarrow\tt{r+10r=9900}\\\\\\\longrightarrow\tt{11r=9900}\\\\\\\longrightarrow\tt{r=\cancel{\dfrac{9900}{11} }}\\\\\\\longrightarrow\tt{\pink{r=Rs.900}}$

We know that formula of loss % :

$\boxed{\bf{Loss\:(\%)=\frac{CP-SP}{CP} \times 100}}}}$

$\underbrace{\bf{2_{nd}\:Case\::}}}}}$

$\bf{We\:have}\begin{cases}\sf{Selling\:price\:(S.P.)_{2}=Rs.990}\\ \sf{Cost\:price\:(C.P.)_{2}=Rs.m}\\ \sf{Loss\:(\%)=10\%}\end{cases}}$

A/q

$\longrightarrow\tt{Loss\:(\%)=\bigg[\dfrac{(C.P.)_{2}-(S.P.)_{2}}{(C.P.)_{2}} \times 100\bigg]}\\\\\\\longrightarrow\tt{\cancel{10}\%=\bigg[\dfrac{m-990}{m} \times 10\cancel{0}\bigg]}\\\\\\\longrightarrow\tt{\%=\dfrac{10m-9900m}{m} }\\\\\\\longrightarrow\tt{m=10m-9900}\\\\\\\longrightarrow\tt{m-10m=-9900}\\\\\\\longrightarrow\tt{-9m=-9900}\\\\\\\longrightarrow\tt{m=\cancel{\dfrac{-9900}{-9} }}\\\\\\\longrightarrow\tt{\pink{m=Rs.1100}}$

So;

Total cost price of Jeans = r + m = Rs.(900+1100) = Rs.2000.

Total selling price of Jeans = Rs.(990 + 990) = Rs.1980.

C.P. > S.P.

Now;

$\longrightarrow\tt{Loss\%=\bigg(\dfrac{C.P.-S.P.}{C.P.} \times 100\%\bigg)}\\\\\\\longrightarrow\tt{Loss\%=\bigg(\dfrac{2000-1980}{2000} \times 100\%\bigg)}\\\\\\\longrightarrow\tt{Loss\%=\bigg(\dfrac{20}{20\cancel{00}}\times\cancel{ 100}\%\bigg)} \\\\\\\longrightarrow\tt{Loss\%=\cancel{\bigg(\dfrac{20}{20}\bigg) \%}}\\\\\\\longrightarrow\tt{\pink{Loss\%=1\%}}$

Thus;

The total loss percent is 1% in whole transaction .