Ankita started paying Rs 400 per month in a 3 year recurring deposit. After six months her brother Anshul started paying Rs 500 per month in 2.5 years recurring deposit. The bank paid 10 % simple interest for both. At maturity who will get more money and by how much ?
Answers
Given :
Amount deposit by Ankita = Rs 400
Time period of deposition = 3 years = 12 × 3 = 36 months
Again
Amount deposit by Anshul = Rs 500
Time period of deposition = 2.5 years = 12 × 2.5 = 30 months
Rate of interest paid by bank = 10%
To Find :
At maturity who will get more money and by how much
Solution :
For Ankita
Principal deposit for 1 months = Amount deposit ×
= Rs 400 ×
= Rs 400 × 18 × 37
= Rs 266400
Now,
Interest =
=
= Rs 2220
So, Maturity Amount = Principal deposit for 1 months + Interest
= Rs 266400 + Rs 2220
= Rs 268620
Again
For Anshul
Principal deposit for 1 months = Amount deposit ×
= Rs 500 ×
= Rs 500 × 15 × 31
= Rs 232500
Now,
Interest =
=
= Rs 1937.5
So, Maturity Amount = Principal deposit for 1 months + Interest
= Rs 232500 + Rs 1937.5
= Rs 234437.5
From both calculation . Rs 234437.5 > Rs 232500
i.e Maturity Amount for Anshul is more than Maturity amount for Ankita.
.
Hence, The Maturity Amount for Anshul is more than Maturity amount for Ankita. Answer
Step-by-step explanation:
In case of Ankita,
Deposit per month=Rs 400
Period (n) =3 years =36 months
Rate of interest=10%
Total principal for one month
=400×n(n+1) /2=400×36(36+1) /2
=400×36×37/2=Rs 266400
Interest=prl/100
=266400×10×1/100×12
=Rs 2220
so, amount of maturity =Rs 400×36+Rs2220
=Rs 14400+ Rs 2220=Rs 16620
In case of anshul
Deposit per month=Rs 500
Rate of intrest=10%
Period(n) =2 whole 1/2=30 months
Total principal of one month
=Rs 500×n(n+1) /2=500×30(30+1) /2
=Rs 500×30×31/2=Rs 232500
Intrest=232500×10×1/100×12=Rs 1937.50
Amount of maturity =Rs 500×30+Rs1937.50
=Rs 16937.50