Ankita travels 14 km to her home partly by rickshaw and partly by bus. She takes half an hour if she travels 2 km by rickshaw, and the remaining distance by bus. On the other and, if she travels 4 km by rickshaw and the remaining distance by bus, she takes 9 minutes longer. Find the speed of the rickshaw and of the bus.
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Distance = 14 km.
Speed = Distance/Time
Time = Distance/Speed
Let The Speed Of Rickshaw = x km/h.
Speed Of Bus = y km/h.
2/x + 12/y = 1/2 ............................ - (1).
& 4/x +10/y = 1/2 + 9/60 = 13/20 .............................. - (2)
Assuming 1/x = u, 1/v = v, we get :
2u + 12v = 1/2 ............................ - (3)
& 4u + 10v = 13/20 ...................................... - (4)
Multiplying Equation 3 by 2 = 4u + 24v = 1 .................................... - (5)
(5) - (4), 14u = 1 - 13/20 = 7/20 ⇒ v = 1/40
From (3), 2u + 12(1/40) = 1/2 ⇒ u = 1/10
∴ Speed Of Rickshaw = x =10 km/h.
& Speed Of Bus = y = 40 km/hr. Answer...............
Speed = Distance/Time
Time = Distance/Speed
Let The Speed Of Rickshaw = x km/h.
Speed Of Bus = y km/h.
2/x + 12/y = 1/2 ............................ - (1).
& 4/x +10/y = 1/2 + 9/60 = 13/20 .............................. - (2)
Assuming 1/x = u, 1/v = v, we get :
2u + 12v = 1/2 ............................ - (3)
& 4u + 10v = 13/20 ...................................... - (4)
Multiplying Equation 3 by 2 = 4u + 24v = 1 .................................... - (5)
(5) - (4), 14u = 1 - 13/20 = 7/20 ⇒ v = 1/40
From (3), 2u + 12(1/40) = 1/2 ⇒ u = 1/10
∴ Speed Of Rickshaw = x =10 km/h.
& Speed Of Bus = y = 40 km/hr. Answer...............
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