ankita wants to make a toran for diwali using some pieces of cardboard . she cut some cardboard pieces as shown below . if perimeter of triangle ADE and triangle BCE are in the ratio 2:3 , then answer the following questions
Answers
Answer:
Given:
R=3cm, H=10.5cm
⇒Surface area = Curved Surface Area + Base Area
=2πrh+πr2
=2×722×3×1010.5+722×3×3cm2
=198+7198cm2
=71584cm2
⇒Area of cardboard sheet used by competitor =71584cm2
⇒Area of cardboard sheet used by 35 competitors =71584×35
=7920cm2
Given : Ankita wants to put a toran by using some pieces of cardboard.
She cuts some pieces of cardboard as shown
Perimeter of triangle ADE and triangle BCE are in the ratio 2:3,
To Find : Length of BC
Length of AD
Length of ED
Length of AE
Solution:
Using Pythagorean Theorem
EB² + EC² = BC²
=> 3² + 4² = BC²
=> 5² = BC²
=> BC = 5
Length of BC is 5 cm
Ratio of corresponding sides of similar triangle is equal
BE/AE = CE/DE
Ratio of corresponding sides of similar triangles = Ratio of perimeter
AD/BC = 2/3
=> AD/5 = 2/3
=> AD = 10/3 cm
ED/CE = 2/3
=> ED/4 = 2/3
=> ED = 8/3 cm
AE/BE = 2/3
=> AE = (2/3) BE
AE = √AD² - DE²
AE = (2/3 )√BC² -CE²
Hence all these 3 are correct
Learn More:
brainly.in/question/14983918
using the concept of Pythagoras theorem construct a segment of ...
brainly.in/question/8399081
draw a tangent segment of length √12 cm the circle with centre o ...
brainly.in/question/13741684
