Ankitesh and his friend Jimmy together sold tickets charity show for Rs 3800.If Ankitesh sold it at a price which is 1 3/8 times of the price at which Jimmy sold it,how much did each of them sell the tickets for?
Answers
Answer:
Let Jimmy sold the tickets for Rsx.
so,Ankitesh sold it for 1 whole 3/8 Times of x =11/8x.
ATQ
x+11/8 x=3800
8x+11x/8=3800 (add by taking lcm)
8x+11x=3800×8
8x+11x=30400
19x=30400
x=30400/19
=1600.
therefore Jimmy sold the tickets for Rs 1600
and Ankitesh sold the tickets for Rs11/8×1600
=Rs2200
Answer:
2200,1600
Step-by-step explanation:
As per the given statement:
Ticket sold by Ankitesh = 1 (3/8) of Jimmy's sold tickets.
Now,
Jimmy's sold tickets + Ankitesh sold tickets = 3800
⇒ Jimmy's sold tickets + 1 (3/8) Jimmy's sold tickets = 3800
⇒ Jimmy's sold tickets[1 + 1 3/8] = 3800
⇒ Jimmy's sold tickets[1 + 11/8] = 3800
⇒ Jimmy's sold tickets [19/8] = 3800
⇒ Jimmy's sold tickets = 3800 * 8/19
⇒ Jimmy's sold tickets = 1600
Now,
Ankitesh's sold tickets = 3800 - 1600 = 2200.
Therefore:
Money collected by Ankitesh = 2200
Money collected by Jimmy = 1600
Hope it helps!