Question

Ankur is painting the walls and ceiling of a cuboidal hall with length height and breadth 12m,10m,6m .from each can of paint 192m2 of area can be painted. How many cans of paint will he need to paint the room

Answer 1

Answer:

Step-by-step explanation:

Area of walls = 360 m^2

Area of the ceiling= 72 m^2

360+72=432 m^2

Now 432÷192 = 2.25

Therefore, 2.25 cans are required

Answer 2

Answer:

3 cans

Step-by-step explanation:

Find Lateral surface area of cuboidal hall and add with Ceilings area then divide with 192 u will get answer