Question

ankur is painting the walls and ceiling of a cuboidal hall with length, breadth and height 12m, 10m, and 6m respectively. from each can of paint 192m² of area can be painted. how many cans of paint will he need to paint the room

Answer 1

hope this answer will help you

Answer 2

Answer:

The number of cans to paint the room is 2

Step-by-step explanation:

• The paint is applied to the surface of the walls. The area would be used for this purpose.
• The Curved surface area of the wall is given by

         $CSA=2h(l+b)$

Step 1 of 1:

• The length, breadth, and height of the cuboid are 12m,10m, and 6m respectively.
• The area of 4 walls of the hall is given by CSA of the cuboid.

           $CSA=2h(l+b)$

           $CSA=2(6)(12+10)\\CSA=12(22)\\CSA=264 m^2$

• Area of the ceiling=l×b

                                       =12×10

                                       =120m²

• Total Area of hall=120+264

                                     =384m²

• Area covered by 1 can=192m²
• Number of cans=$\frac{384}{192}$= 2 cans