Question

Ankur is painting the walls and ceiling of a cuboidal hall with length breath and ght 12m 10m and 6m respectively.from each can of paint 192 m^2 of area can be painted . How many cans of paint will he need to paint the room

Answer 1

hiii!!!

here's ur answer...

ATQ,


we have to find the cost of painting the walls and ceiling of the hall.

so, we will use CSA + 1 base formula.

given :-

length of the hall = 12m

breadth of the hall = 10m

height of the hall = 6m

CSA + 1 base of the hall = 2h ( l + b ) + lb

= 2 × 6 ( 12 + 10 ) + ( 12 × 10 )

= ( 12 × 22 ) + 120

= 264 + 120

= 384m²

if one can of paint is required to paint 192m²

therefore no. of cans required to paint 384m²

= 384/192

= 2

hence, 2 cans are required to paint the walls and ceiling of the hall.

hope this helps..!!