Question

Anna bought soil that contains 12% of water. She wants to plant a flower that need
18% of water. How much water does she need to pour in 2 kg of soil to plant that
flower?​

Answer 1

Given:

Anna bought soil that contains 12% of the water. She wants to plant a flower that needs 18% of water.

To find:

How much water does she need to pour in 2 kg of soil to plant that

flower?​

Solution:

The percentage of water in the soil Anna bought was = 12%

So,

The quantity of water in 2 kg of that soil is,

= $\frac{12}{100} \times 2$

= $0.24\:units$

Let's consider that she needs to pour "x" units of water in 2 kg of soil.

Then,

The total water content now becomes = (0.24 + x) units

and

The total weight of soil now becomes = (2 + x) units

Now, as per the question, we can form the equation as:

$\frac{18}{100} (2 + x) = 0.24 + x$

$\implies 36 + 18x = 24 + 100x$

$\implies 100x - 18x = 36 - 24$

$\implies 82x = 12$

$\implies x = \frac{12}{82}$

$\implies \bold{x = 0.146\:units}$

Thus, Anna needs to pour 0.146 units of water in 2 kg of soil to plant that

flower.

[Note: the unit of measurement of water can be taken as kg or litre]

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