Anne needs to pack 6-cm cubes into a box measuring 33 cm by 15 cm by 27 cm as shown below. What is the volume(in cm cube) of the remaining space in the box after the maximum number of cubes have been packed in?
Attachments:
Anonymous:
4725???
Answers
Answered by
5
Hey bro!
Here is your answer !
Final result: 4725
Things to know :
1) Integral part of 1.5 is 1
Integral part of 15/6 = Integral part of 2.5 = 2
Now, on Question side
According to the question , we get
Max. No. of 6-cm cubes that can be packed along the lenght (15 cm )
= Integral part of (15/6)
= 2
Max. No. of 6-cm cubes that can be packed
along breadth (33 cm)
= integral part of (33/6)
= integral part of (5.5)
= 5
Max . No. of cubes that can be packed along
height(27 cm)
=integral part of (27/6)
= integral part of ( 4.5)
=4
Now,
Max . No. of cubes that can be packed in box
= 2*5*4
= 40.
Then,
After filling these small cubes ,
Volume of remaining space =
Volume of box - no. of cubes of 6 cm * Volume of 1 cube of 6cm
= 33 * 15 *27 - 40* 6*6*6
= 13,365-8640
= 4725cm^3
Hope, you understand my answer and it helps you !!!!
Here is your answer !
Final result: 4725
Things to know :
1) Integral part of 1.5 is 1
Integral part of 15/6 = Integral part of 2.5 = 2
Now, on Question side
According to the question , we get
Max. No. of 6-cm cubes that can be packed along the lenght (15 cm )
= Integral part of (15/6)
= 2
Max. No. of 6-cm cubes that can be packed
along breadth (33 cm)
= integral part of (33/6)
= integral part of (5.5)
= 5
Max . No. of cubes that can be packed along
height(27 cm)
=integral part of (27/6)
= integral part of ( 4.5)
=4
Now,
Max . No. of cubes that can be packed in box
= 2*5*4
= 40.
Then,
After filling these small cubes ,
Volume of remaining space =
Volume of box - no. of cubes of 6 cm * Volume of 1 cube of 6cm
= 33 * 15 *27 - 40* 6*6*6
= 13,365-8640
= 4725cm^3
Hope, you understand my answer and it helps you !!!!
Similar questions