Math, asked by saniya3721, 6 months ago

Anne's mother orders N boxes of sweets for Christmas. Each box contains 20 sweets. In one of the boxes, the sweets are found to be spoilt. Also x sweets are found crushed and cannot be offered to guests. How many sweets can Anne's mother give her guests?
options:
a. 20N- x
b. 20 [N-1]-x
c. 19N-x
d. [N-1-x] into 20
PROVIDE EXPLANATION

Answers

Answered by Anonymous
12

Answer:

20 (N-1) - x = sweet to be given to guests

Step-by-step explanation:

Boxes of sweets = N

Number of sweets in each box = 20

Number of boxes spoilt = 1

Number pf sweets crushed = x

Anne's mother bought N times of 20 sweets = 20 raised to N = 20 (N)

Box spoilt - Minus one from N since we are talking about a BOX = (N - 1)

20 (N - 1) - x = sweets to be given out

20 raised to N, subtract 1 and subtract the crushed sweets = sweets to be given to guests

Hope it helps, please mark as brainliest

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