anneyonghaseyo chingus /hello frnz
Answer any one of these questions maybe it will sound helpful to me
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Hello mate ✌️
Step-by-step explanation:
Answer
A rectangle has all its angles = 90°
Thus, /_A = 90°
Now, E is midpoint of AD. Therefore;
AE = 1/2 × AD
AE = 1/2 × 40
AE = 20 cm
AB = 48 cm (Given)
By applying the Pythagoras Theorem in Triangle AEB:
=>
=>
=> EB = 52 cm
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Given D and E are point on sides AB and AC respectively of triangle ABC such that Area(ΔDBC) = Area(ΔEBC).
Given that Area(ΔDBC) = Area(ΔEBC).
Then the height of triangle DBC and Triangle EBC are the same because both triangles are the same
Then it possible that both triangle on the same base and between parallel line BC and DE
Therefore, they will lie between the same parallel lines.
∴BC∥DE [henceproved]
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