Question

Annie designed a room in a rectangular shape where the length of the rectangle is 4

times its width. If the perimeter of the rectangle is 80 m, find the length and breadth of

rectangle.​

Answer 1

• Length of rectangle is 32 m.
• Breadth of rectangle is 8 m.

Step-by-step explanation:

To find:-

• Length of rectangle.
• Breadth of rectangle.

Solution:-

Given that,

Annie designed a room in a rectangular shape. Where the length of rectangle is 4 times it's width(or Breadth).

Perimeter of rectangular room is 80 m.

Let, Breadth of rectangle be x.

And Length of rectangle be 4x. [We take length be 4x because it is given Length is 4 times its width]

$\boxed{\bold{Perimeter \: of \: rectangle = 2(Length + Breadth)}}$

➝ 80 = 2×(4x + x)

➝ 80 = 8x + 2x

➝ 80 = 10x

➝ 80/10 = x

➝ 8 = x

Or, x = 8

Verification:-

➝ 80 = 2×(4x + x)

• Put x = 8.

➝ 80 = 2 × (4×8 + 8)

➝ 80 = 2 × (32 + 8)

➝ 80 = 64 + 16

➝ 80 = 80

Hence, Verified!!

We have taken Breadth be x. So, Breadth of rectangle is 8 m.

We have also taken Length be 4x = 4×8 = 32. Thus, Length of rectangle is 32 m.

Answer 2

Step-by-step explanation:

80 = 2×(4x + x)

=>80 = 8x + 2x

=>80 = 10x

=> 80/10 = x

=> 8 = x