Question

annual growth of population of town is 12% if present population is 186040 what it was 2 years ago

Answer 1

2 per annum = 15. %. 2 per annum,. T = 1 year. If interest compounded semi-annually. Then. R = 15.2 2.. = 15. 4. % per half yearly. T = 1 2 = 2 half years. ...... Rate of growth, R = 12% p.a., T = 2 years. Present population, P = 186040. Population 2 years before, P0 = ? P = 0 1. 100. T. R. P. ⎛. ⎞. +. │. │. ⎝. ⎠. 186040 = 2.

Answer 2

Answer: 144,069.376 was the population 2 years ago.