Math, asked by sarlagautam95, 8 days ago

annum, find the amount the woman 1 9. If? 12800 be borrowed for 3 years at the rate of 6 \times \frac{1}{2} p.a., find the C.I. to be paid on it


Answers

Answered by βαbγGυrl
0

Answer:

It is given that

Principal = ₹ 46875

Rate of interest = 4% p.a.

(i) Interest for the first year = Prt/100

Substituting the values

= (46875 × 4 × 1)/ 100

= ₹ 1875

So the amount after first year or principal for the second year = 46875 + 1875 = ₹ 48750

Here

Interest for the second year = (48750 × 4 × 1)/ 100

So we get

= ₹ 1950

(ii) We know that

Amount at the end of second year = 48750 + 1950

= ₹ 50700

(iii) Interest for the third year = (50700 × 4 × 1)/ 100 = ₹ 2028

Answered by Jiya0071
0

Step-by-step explanation:

P=Rs.12800

Period =1 year

∴Half yearly periods N=2

Rate of interest =7

2

1

=

2

15

%p.a

∴Half yearly interest =

2

1

×

2

15

=

4

15

%

A=P(1+

100

R

)

N

=12800(1+

100

15/4

)

2

=12800(

400

400+15

)

2

=12800×

400

415

×

400

415

=Rs.13778

Compound interest =A−P

=Rs.(13778−12800)

=Rs.978

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