Question

Annyeong mates ❤


Kindly,Can someone please do me the two sums ?

i) 14/x+y + 3/x-y = 5

21/x+y - 1/x-y = 2


ii) x+a/a = y+b/b

ax- by = a²- b²


Kindly please do me the sums .... I'll be really grateful .... ❤❤

Answer 1

heya

here is your solution

Step-by-step explanation:

i) 14/x+y + 3/x-y = 5

21/x+y - 1/x-y = 2

14/x +y+3/x -y =5

==> 14/x +3/x =5

==>17/x =5

==> x = 17/5

putting it in second eq.

21/(17/5) +y-1 / {(17/5)-y}. =2

==> y-1 / (17/5)-y = 2-105/7

==> 5(y-1)/17-5y = -88/7

==> 5y-5 = ( -88/7)(17-5y)

==>5y-5 =( -1496-440y)/7

==>35y-35 = -1496-440y

==>35y+440y = -1496 +35

==> 475y = -1461

y = -1461/475

ii) x+a/a = y+b/b  

ax- by = a²- b²

x/a + y/b = 2

ay + xb = 2ab----------( 1 )

ax - by = a² - b²---------( 2 )

from-----( 1 ) &-------( 2 )

multiply ( 1 ) by "a" ( 2 ) by "b"

abx + a²y = 2a²b

abx - b²y = ba² - b³

-------------------------------------------------

y(a² + b²) = 2a²b - ba² + b³

y(a² + b²) = a²b + b³

y(a² + b²) = b(a² + b²)

y = b [ put in -----( 1 )]

we get,

ay + xb = 2ab

a(b) + xb = 2ab

xb = 2ab - ab

x = ab/b

x = a

hope its help you

thanx and be barinly........................................

Answer 2

let. 1/x+y=u

or. 1/x-y=v

so. 14/x+y=14u.

3/x-y=3v.

eqn is 14u+3v=5

21u-1v =2

by elimination method

3(14u+3v=5)

2(21u-1v=2)

subtract

.42u+9v=15

42u-2v=4

- + -

_____________

11v=11

v=1

put v=1 in any eqn

14u+3(1)=5

14u=5-3

u=2/14 or 1/7

v=1/x-y

1=1/x-y

x-y=1. eqn 1..

u=1/x+y

1/7=1/x+y

x+y=7. eqn 2

from eqn 1and 2

x =4

and y=3

part 2.

x+a/a=y+b/b

x+a/a-(y+b)/b=0

((x+a)b-a(y+b))/ab=0

xb+ab-ay-ab=0

xb-ay=0. eqn 1

&

ax-by=a²-b² eqn 2

by elimination method

b(ax-by=a²-b²)

a(xb-ay=0)

abx-b²y=b(a²-b²)

abx-a²y=0

- + -

---------------------------

y(a²-b²)=b(a²-b²)

y=b

put in any eqn we get

.x=a

.plz mark as brainliest answer