Anobject having a velocity4.0m/s is accelerated at the rate of 1.2m/s square for 5.0s.Find the distance travelled during the period of acceleration
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Let distance be s.
acceleration be a.
initial velocity be u .
time be t.
so,y
s=ut+1/2at²
=4×5+1/2×1.2×5²
=20+0.6×25
=20+15
=35m.
Hope it helps.
plz mark this as the brainliest.
acceleration be a.
initial velocity be u .
time be t.
so,y
s=ut+1/2at²
=4×5+1/2×1.2×5²
=20+0.6×25
=20+15
=35m.
Hope it helps.
plz mark this as the brainliest.
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