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anshikapal751
Secondary SchoolPhysics 5+3 pts
Two forces 3 N & 2N are at an angle theta such that the resultant is R. The 1st force is now increased to 6 N & the resultant become 2R. Find the value of theta.
Report by Falgunichapekar 03.08.2017
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anshikapal751
Anshikapal751 · Ace
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AionAbhishek
AionAbhishek Ace
Here
Formula used
R^2 = A^2 + B^2 + 2AB Cos theta
A= 3 N
B= 2 N
R^2 = 13 + 12 Cos theta
Case 2
4R^2 = 40 + 24 Cos theta
put the value of R^2
here we got
4 ( 13 + 12 Cos theta ) = 40 + 24 Cos theta
52 + 48 Cos theta = 40 + 24 Cos theta
Now 24 Cos theta = 40-52
Cos theta = -12 / 24
Cos theta = -1/2
Cos 120 degree = -1 /2
Theta = 120 degree
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