Question

[Ans: 1.92 A
10. The magnetic field at the centre of a
circular current carrying loop of radius
12.3 cm is 6.4 x 10-6 T. What will be the
magnetic moment of the loop?
[Ans: 5.954 x 10-2 A.m?]​

Answer 1

Explanation:

Let r be the radius of the circular loop.

∴ A = πr

2

or r =

π

A

Magnetic field at the centre of the loop is

B =

2r

μ

0

I

=

2

π

A

μ

0

I

or I=

μ

0

2B

π

A

The magnetic moment of the loop is

M= IA =

μ

0

2B

π

A

A =

μ

0

π

2BA

A

hope it helps plzz mark as brainliest

Answer 2

Answer:

5.938x10⁻² Am

Explanation:

Magnetic field at the center of the loop is μ₀I/2r

I = Bx2r/μ₀ = 6.4x 10⁻⁶x2x12.3x10⁻²/ 4πx10⁻⁷

= 1.25 A

Magnetic moment of the loop, M =IA

M = 1.25 x π(12.3x10⁻²)²

= 5.938x10⁻²Am