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15. Calculate the angle between the vectors :
(1) A= 2(+2j-k, B = 6i-3j+ 2 &
(1) A = i +29- |, B =- î+j-2 î
(iii) A = i + j + k, B=-2 i
(iv) A=4 î+6j-3 , B=-2î - 5 j+7 î
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- A
A A
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- ABcosθ=A.B
A.B=(2I+2J-K).(6I-3J+2K)=12-6-2
=4
MAGNITUDE OF A=√(2)²+(2)²(-1)²=√9
MAGNITUDE OF B=√(6)²+(-3)²+(2)²=√49
COSθ=A.B/AB
COSθ=4/√9√49
θ=COS⁻¹(4/√4√49
IN ALL PARTS PROCEDURE IS SAME
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