Question

[Ans. 2.4 s]
194/ The displacement of a particle at an instant t is given as x = - 15t² + 20t + 30m Calculate it's position & velocity at t =0second​

Answer 1

Explanation:

$x = - {15}t^{2} + 20t + 30 \\ \binom{dx}{dt} = v = - 30t + 20 \\ now \: velocity \: at \: t = 0 \: will \: be \\ v(0) = 20m {s}^{ - 1} \\ position \: at \: t = 0 \: will \: be \\ x(0) = 30m$