Question

Ans
4. Calculate the Co-efficient of friction.
15
Find the horizontal force required to move a body weighing 200 kg on a rough horizontal
having Co-efficient of friction 0.35.
[ Ans = 70 kg. wt.)
​

Answer 1

Answer:

The solution have been attached.

Answer 2

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Calculate the Co-efficient of friction 15.

Find the horizontal force required to move a body weighing 200 kg on a rough horizontal

having Co-efficient of friction 0.35.

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The force required to move the body is 686 N.

Step-by-step explanation:

Mass of the body = 200 kg

Coefficient of friction = 0.35

Force required to move the body = ??

$\bigstar \: \boxed{\sf{F = \mu N}}★ F=μN$

$\sf{N = {m \times g}}$  so, replacing it in the formula, it forms,

$\sf{F =\mu \times \: m \times g}$

$\muμ$ = 0.35

m = 200 kg

g = 9.8 m/s²

$g = 9.8 m/s²\longrightarrow{\sf{F = 0.35 \times 200 \times 9.8}}\longrightarrow{\sf{F = 70 \times 9.8}}\longrightarrow{\sf{F = 686 \: N}}$

Force required = 686 N

Therefore, the force required to move the body is 686 N.