Question

ans........... ........​

Answer 1

here is ur answer↑

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Answer 2

${\huge {\mathfrak {Answer :-}}}$

In $\triangle$ ADC and $\triangle$ ADB,

(I) AD is common.

(II) $\angle$ ADB = $\angle$ ADC.

(III) BD = DC.

So, $\triangle$ ADC is congruent to $\triangle$ ADB.

So, AB = AC (by cpct).

Hence, $\triangle$ ABC is a isosceles triangle.

Done.. ✔️

=_='