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Hi Mate Here is ur answer...
By elimination method :
8x+5y = 9---------(1) ×2
3x+2y = 4 -----(2). ×5
we get,
16x+10y = 18
15x+10y= 20
subtracting both the equations we get;
x = -2
Putting the value of x in (1)...
8×-2 +5y = 9
-16+5y = 9
5y = 9+16
5y = 25
y = 25/5
y = 5
===================
Hope this helped u...
me in 9th and u
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HeLo
Solutions:-
⬇️⬇️⬇️⬇️
♻️♻️By the substitution method :-♻️♻️
8x+5y=9------(1)
3x+2y=4------(2)
From equation 1
8x=9-5y
x=9-5y/8-------(3)
put the value of x in equation 2
3x+2y=4
3(9-5y/8)+2y=4
27-15y/8+2y=4
27-15y+16y=32
y=32-27
y=5----(4)
put the value of y in equation (3)
x=9-5y/8
x=9-5×5/8
x=9-25/8
x=-16/8
x=-2
Solutions:-
⬇️⬇️⬇️⬇️
♻️♻️By the substitution method :-♻️♻️
8x+5y=9------(1)
3x+2y=4------(2)
From equation 1
8x=9-5y
x=9-5y/8-------(3)
put the value of x in equation 2
3x+2y=4
3(9-5y/8)+2y=4
27-15y/8+2y=4
27-15y+16y=32
y=32-27
y=5----(4)
put the value of y in equation (3)
x=9-5y/8
x=9-5×5/8
x=9-25/8
x=-16/8
x=-2
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