Question

ANS, (a)
Find the acceleration of an object of mass 200
gm when a force of 1.2N acts on it:
(a) 6m/sec
(6) 6 m/sec2
(c) 6 m/sec (d) 6 m/sec2​

Answer 1

Given

Mass = 200 gm

Force = 1.2 N

To Find

Acceleration

Solution

We know that

$\sf \longrightarrow a=\dfrac{F}{m}$

Here

• a = Acceleration
• F = Force
• m = Mass

Units

• a = metre/second squared (m/s²)
• F = Newton (N)
• m = kilogram (kg)

According to the question

We are asked to find acceleration

Therefore

We must find "a"

Given that

Mass = 200 gm

Force = 1.2 N

Hence

• m = 200 gm = 0.2 kg
• F = 1.2 N

Substituting the values

We get

$\sf \longrightarrow a=\dfrac{1.2}{0.2} \ m/s^{2}$

$\sf \longrightarrow a=\dfrac{12}{2} \ m/s^{2}$

Therefore

$\sf \longrightarrow a= 6 \ m/s^{2}$

Hence

Acceleration = 6 m/s²

So

Option (b) and (d) are correct

Answer 2

Answer:

Given :-

• An object of mass 200 gm when a force of 1.2 N acts on it.

To Find :-

• What is the acceleration.

Formula Used :-

By using Newton's Second law of motion we know that,

✦ F = ma ✦

Now, we get

$\tt\boxed{\bold{\large{a\: =\: \dfrac{F}{m}}}}$

where,

• F = Force
• m = Mass
• a = Acceleration

Solution :-

Given :

• Force = 1.2 N
• Mass = 200 gm = $\tt\dfrac{200}{1000}$ = 0.2 kg

According to the question by using the formula we get,

⇒ $\tt{a\: =\: \dfrac{1.2}{0.2}}$

⇒ $\tt{a\: =\: \dfrac{12 \times {\cancel{10}}}{2 \times {\cancel{10}}}}$

⇒ $\tt{a\: =\: \dfrac{\cancel{12}}{\cancel{2}}}$

➠ $\tt\green{a\: =\: 6\: m/{s}^{2}}$

$\therefore$ The acceleration of an object is 6 m/s².

Hence, the correct options is option no (b) and (d) are same option that is 6 m/s² .