Ans both questions........
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(1)
a^7 - ab^6
= > a(a^6 - b^6)
= > a((a^3)^2 - (b^3)^2)
= > a((a^3 + b^3)(a^3 - b^3))
= > a((a + b)(a^2 - ab + b^2)(a - b)(a^2 + ab + b^2)
= > a(a + b)(a - b)(a^2 - ab + b^2)(a^2 + ab + b^2)
(2)
Given Equation is (x^2 + 4x + 4)(x^2 + 6x + 9)
= > (x^2 + 2x + 2x + 4)(x^2 + 3x + 3x + 9)
= > (x(x + 2) + 2(x + 2))(x(x + 3) + 3(x + 3))
= > (x + 2)(x + 2)(x + 3)(x + 3)
= > (x + 2)^2(x + 3)^2.
= > (x + 2)(x + 3)
= > x^2 + 3x + 2x + 6
= > x^2 + 5x + 6.
Hope this helps!
a^7 - ab^6
= > a(a^6 - b^6)
= > a((a^3)^2 - (b^3)^2)
= > a((a^3 + b^3)(a^3 - b^3))
= > a((a + b)(a^2 - ab + b^2)(a - b)(a^2 + ab + b^2)
= > a(a + b)(a - b)(a^2 - ab + b^2)(a^2 + ab + b^2)
(2)
Given Equation is (x^2 + 4x + 4)(x^2 + 6x + 9)
= > (x^2 + 2x + 2x + 4)(x^2 + 3x + 3x + 9)
= > (x(x + 2) + 2(x + 2))(x(x + 3) + 3(x + 3))
= > (x + 2)(x + 2)(x + 3)(x + 3)
= > (x + 2)^2(x + 3)^2.
= > (x + 2)(x + 3)
= > x^2 + 3x + 2x + 6
= > x^2 + 5x + 6.
Hope this helps!
siddhartharao77:
:-)
Answered by
2
Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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