Question

......ans can any1.....

Answer 1

between

to

by

for

since

to

with

at

in

beside

within

in

for

to

at

Answer 2

Answer:

$Answer:</p><p> </p><p> </p><p> </p><p> </p><p></p><p>\green{\tt{\therefore{Value\:of\:xy=30}}}∴Valueofxy=30</p><p>\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}} </p><p>Step−by−stepexplanation:</p><p> </p><p> </p><p> </p><p> </p><p></p><p>\begin{lgathered}\green{\underline \bold{Given :}} \\ \tt: \implies x + y = 8 \\ \\ \tt: \implies {x}^{2} + {y}^{2} =4 \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies xy =?\end{lgathered} </p><p>Given:</p><p> </p><p> </p><p>:⟹x+y=8</p><p>:⟹x </p><p>2</p><p> +y </p><p>2</p><p> =4</p><p>ToFind:</p><p> </p><p> </p><p>:⟹xy=?</p><p> </p><p> </p><p></p><p>• According to given question :</p><p>\begin{lgathered}\bold{As \: we \: know \: that} \\ \tt: \implies {x}^{2} + {y}^{2} = {(x + y)}^{2} - 2xy \\ \\ \tt: \implies 4 = {8}^{2} - 2xy \\ \\ \tt: \implies 4 = 64 - 2xy \\ \\ \tt: \implies 4 - 64 = - 2xy \\ \\ \tt: \implies - 60 = - 2xy \\ \\ \tt: \implies xy = \frac{ - 60}{ - 2} \\ \\ \green{\tt: \implies xy = 30} \\ \\ \green{\tt \therefore Value \: of \: xy \: is \: 30} \\ \\ \blue{ \boxed{ \bold{Some \: related \: formula}}} \\ \orange{\tt \circ \: \: {(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab} \\ \\ \orange{\tt \circ \: \: {(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab} \\ \\ \orange{\tt \circ \: \: a^{2} + {b}^{2} = {(a - b)}^{2} + 2ab} \\ \\ \orange{\tt \circ \: \: {a}^{2} - {b}^{2} = (a + b)(a - b)} \\ \\ \orange{\tt \circ \: \: {(a + b)}^{3} = {a}^{3} + {b}^{3} + 3{a}^{2} b + {3ab}^{2} } \\ \\ \orange{\tt \circ \: \: {(a - b)}^{3} = {a}^{3} - {b}^{3} - 3{a}^{2} b + {3ab}^{2} }\end{lgathered} </p><p>Asweknowthat</p><p>:⟹x </p><p>2</p><p> +y </p><p>2</p><p> =(x+y) </p><p>2</p><p> −2xy</p><p>:⟹4=8 </p><p>2</p><p> −2xy</p><p>:⟹4=64−2xy</p><p>:⟹4−64=−2xy</p><p>:⟹−60=−2xy</p><p>:⟹xy= </p><p>−2</p><p>−60</p><p> </p><p> </p><p>:⟹xy=30</p><p>∴Valueofxyis30</p><p>Somerelatedformula</p><p> </p><p> </p><p>∘(a+b) </p><p>2</p><p> =a </p><p>2</p><p> +b </p><p>2</p><p> +2ab</p><p>∘(a−b) </p><p>2</p><p> =a </p><p>2</p><p> +b </p><p>2</p><p> −2ab</p><p>∘a </p><p>2</p><p> +b </p><p>2</p><p> =(a−b) </p><p>2</p><p> +2ab</p><p>∘a </p><p>2</p><p> −b </p><p>2</p><p> =(a+b)(a−b)</p><p>∘(a+b) </p><p>3</p><p> =a </p><p>3</p><p> +b </p><p>3</p><p> +3a </p><p>2</p><p> b+3ab </p><p>2</p><p> </p><p>∘(a−b) </p><p>3</p><p> =a </p><p>3</p><p> −b </p><p>3</p><p> −3a </p><p>2</p><p> b+3ab </p><p>2$