Question

Ans correctly spam ans will be deleted acct..​

Answer 1

Answer:

Hey⚡❤️

Hello.

This problem is from trigonometry. So there are different formulas for sin,cos,tan etc.

Like for sin(x) if measured in radians is equals to sin(x)= x-x^3/3!-x^5/5!…..

So now sin(x)/x= 1-x^2/6-x^3/120…..

If x is small, we get, sin(x)/x = 1-x^2/6

Now if we compare the values of sin(x)/x as given in the question and derived by us, we get

==> 1-x^2/6 = 2165/2166

==> x^2 = 361

==> x= +- 19 (taking square root both the sides)

So we get value of x as +19 and -19.

Let me know if this was helpful or

Answer 2

$\mathfrak\red{AnsweR}$

=> sin(x)/x = 1-x^2/6

=> 1-x^2/6 = 2165/2166

=> 1–2165/2166 =x^2/6

=> 1-x^2/6 = 2165/2166

=> 1–2165/2166 =x^2/6

=> 1/2166 = x^2/6

=> x^2 = 6/2166 (cross multiplication)

=> x^2 = 361

=> x= +- 19 (taking square root both the sides)

So we get value of x as +19 and -19.