Chemistry, asked by ZiaAzhar89, 11 months ago

✌✌Ans — D✌✌

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Answers

Answered by sagarnirapure914
21

Answer:

Option (D) is correct.

Explanation:

for (A) :

H3PO3, on heating undergoes disproportionation reaction to form PH3 and H3PO4.

Thus, Option (A) is incorrect.

for (B) :

Here, H3PO3 is a strong reducing reagent.

H3PO2 is a stronger reducing reagent.

Whereas, H3PO4 is a weaker reducing reagent.

Thus, the reducing property is not so well applied for H3PO4

Hence, Option (B) is also incorrect.

for (C) :

In H3PO2 (Hypophosphorus acid)

  • one OH group is present
  • It is monobasic in nature.

In H3PO3 (Phosphorus acid)

  • two OH groups are present
  • It is dibasic in nature

In H3PO4 (Orthophosphoric acid or phosphoric acid)

  • three OH groups are present
  • It is tribasic in nature

for (D) :

H3PO2 is prepared by alkaline hydrolysis of phosphorus.

P4 + 3OH^- + 3H2O ----> PH3 + 3H2PO2^-

H2PO2^- + H^+ ----> H3PO2

The P in H3PO2 is the +1 oxidation state. It is monobasic and very strong reducing agent.

Salts of this acid are called Hypophosphates. NaH2PO2 is used to bleach wood pulp in the paper industry.

Thus, option (D) is correct .

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Answered by SainaPaswan
0

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Option(D)

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